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Question

A+BA3B2 (unbalanced) A3B2+CA3B2C2 (unbalanced) Above two reactions are carried out by taking 3 moles each of A and B and by taking one mole of C. Then which option(s) is/are correct?



Your Answer
A

1 mole of A3B2C2 is formed.

Correct Answer
B

12 mole of A3B2C2 is formed.

Your Answer
C

12 mole of A3B2 is formed.

Correct Answer
D

12 mole of A3B2 is left finally.


Solution

The correct options are
B

12 mole of A3B2C2 is formed.


D

12 mole of A3B2 is left finally.


3A+2BA3B2A/c to3 moles2 moles1 molestiochilometryGiven:3 moles3 moles

3 moles of A react with 2 moles of B to give 1 mole of A3B2. Hence 1 mole of B would be left unreacted.

A3B2+2CA3B2C21 mole2 mole1 mole(A/c to stoichiometry)1 mole1 mole(Given)(from abovereaction)

2 moles of C reacts with 1 mole A3B2 to give 1 mole A3B2C2. So, 1 mole of C will react with 12 mole of A3B2 to give 12 mole of A3B2C2. So, 12 mole of A3B2 is left.

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