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Question

A bag contains 50 tickets numbered 1, 2, 3, ..., 50 of which five are drawn at random and arranged in ascending order of magnitude (x1<x2<x3<x4<x5). The probability that x3=30 is

A
20C250C5
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B
29C250C5
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C
20C2×29C250C5
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D
None of these
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Solution

The correct option is D 20C2×29C250C5
First and second number should be from tickets numbered 1 to 29=29C2 ways and remaining two in 20C2 ways
Therefore, favorable number of events
=29C2×20C2
Required probability=29C2×20C250C5

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