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Question

A bag contains 6 red and 9 blue balls. Two successive drawing of four balls are made such that the balls are not replaced before the second draw. Find the probability that the first draw gives 4 red balls and second draw gives 4 blue balls.
  1. 7715
  2. None of these
  3. 3715
  4. 15233


Solution

The correct option is C 3715
Let A be the event drawing 4 red ball in first draw and B be the event of drawing 4 blue balls in the second draw.
Then P(A)=6C415C4=51365=191
P(BA)=9C411C4=126330=2155
Hence, the required probability = P(AB)
=P(A)P(BA)
=191×2155=3715

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