A bag contains a black ball, a red ball and a green ball, all the balls are identical in shape and size. A ball is drawn from the bag without looking into it. What is the probability that the ball drawn is:
Not a red ball

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Solution

A bag contain a black ball a red ball and agreen ball.
Possible out comes $= 1 + 1 + 1 = 3$
No. of favourable outcomes $= 2 ∵$ not a red ball thats mean a green ball or a black ball.
$P (E) = \frac{2}{3}$

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A bag contains a black ball, a red ball and a green ball, all the balls are identical in shape and size. A ball is drawn from the bag without looking into it. What is the probability that the ball drawn is:Not a red ball

A bag contain a black ball a red ball and agreen ball.Possible out comes =1+1+1=3No. of favourable outcomes =2∵ not a red ball thats mean a green ball or a black ball.P(E)=23

A bag contains a black ball, a red ball and a green ball, all the balls are identical in shape and size. A ball is drawn from the bag without looking into it. What is the probability that the ball drawn is:
Not a red ball

A bag contain a black ball a red ball and agreen ball.
Possible out comes $= 1 + 1 + 1 = 3$
No. of favourable outcomes $= 2 ∵$ not a red ball thats mean a green ball or a black ball.
$P (E) = \frac{2}{3}$