Question

A bag contains a red ball, a blue ball and a yellow ball, all the balls being of the same size. Kritika takes out a ball from the bag without looking into it. What is the probability that she takes out the
$\left(1\right)$ Yellow ball
$\left(2\right)$ Red ball
$\left(3\right)$ Blue ball?

• A. $\left(1\right)\frac{1}{2}\left(2\right)\frac{1}{3}\left(3\right)\frac{1}{2}$
• B. $\left(1\right)\frac{1}{3}\left(2\right)\frac{1}{2}\left(3\right)\frac{1}{3}$
• C. $\left(1\right)\frac{1}{3}\left(2\right)\frac{1}{3}\left(3\right)\frac{1}{3}$
• D. $\left(1\right)\frac{1}{2}\left(2\right)\frac{1}{2}\left(3\right)\frac{1}{2}$

Answer 1

The correct option is C $\left(1\right)\frac{1}{3}\left(2\right)\frac{1}{3}\left(3\right)\frac{1}{3}$

Since, Total no. of balls=3
1.) No. of yellow balls=1
$\therefore$ probability of getting a yellow ball=$\frac{1}{3}$
2.) No. of red balls=1
$\therefore$ probability of getting a red ball=$\frac{1}{3}$
3.) No. of blue balls=1
$\therefore$ probability of getting a blue ball=$\frac{1}{3}$