Question

A bag contains n white and n red balls. Pairs of balls are drawn with out replacement until the bag is empty. The probability that each pair consists of one white and one red ball is

• A. $\frac{\angle n.\angle n}{\angle 2n}{.2}^{n-1}$
  
• B. $\frac{\left(\angle n\right){.2}^n}{\angle 2n}$
  
• C. $\frac{(\angle n{)}^2{.2}^n}{\angle 2n}$
  
• D. $\frac{\left(\angle n\right){.2}^{n-1}}{\angle 2n}$

Answer 1

The correct option is C $\frac{(\angle n{)}^2{.2}^n}{\angle 2n}$


$n\left(s\right)=2n_{C_2}.2n-2_{C_2}...{.2}_{C_2}n\left(E\right)=n^2(n-1{)}^2(n-2{)}^2..{.1}^2=(\angle n{)}^2$