Question

# A balanced equation for combustion of methane is given below:CH4(g)+2O2(g)→CO2(g)+2H2O(g)Which of the following statements is not correct on the basis of the above chemical equation?

A
One mole of CH4 reacts with 2 moles of oxygen to give one mole of CO2 and 2 moles of water.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
One molecule of CH4 reacts with 2 molecules of oxygen to give one molecule of CO2 and 2 molecules of water.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
22.4 L methane reacts with 44.8L of oxygen to give 44.8L of CO2 and 22.4 L of water
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
16 g of methane reacts with 64 g of O2 to give 44 g of CO2 and 36 g of water.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C 22.4 L methane reacts with 44.8L of oxygen to give 44.8L of CO2 and 22.4 L of waterCH4(g)+2O2(g)→CO2(g)+2H2O(g)Since 1 mole methane = 12+4×1=16 g and 2 mole oxygen =2×32=64 g, 1 mole CO2=12+32=44 g and 2 mole water=2×18=36 gFrom the balanced reaction: One mole(or 1 molecule or 16 g) of CH4 reacts with 2 moles (or 2 molecules or 64 g) of oxygen to give one mole (or 1 molecule or 44 g) of CO2 and 2 mole (or 2 molecules or 36 g) of water.For the gaseous system at STP:22.4 L methane reacts with 44.8 L of oxygen to give 22.4 L of CO2 and 44.8 L of water.

Suggest Corrections
0
Join BYJU'S Learning Program
Select...
Related Videos
Volume of Gases and Number of Moles
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
Select...