Question

A ball crosses point p with speed 6 $m/s$ and returns same point p with speed 8 $m/s$ in 5 seconds. Assuming acceleration($a$) is uniform, find the magnitude of $a$

• A. $\frac{8}{5}m/s^2$
• B. $\frac{6}{5}m/s^2$
• C. $\frac{5}{5}m/s^2$
• D. $\frac{14}{5}m/s^2$

Answer 1

The correct option is D $\frac{14}{5}m/s^2$

$a=\frac{v_f-v_i}{t}$
where, $v_f$ is the final velocity,
and $v_i$ is the initial velocity.
$a=\frac{(-8)-(+6)}{5}=\frac{-14}{5}m/s^2$