A ball is released from the top of a tower. The ratio of work done by force of gravity in first, second and third second of the motion of the ball is

1 : 2 : 3

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1 : 4 : 9

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1 : 3 : 5

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1 : 5 : 3

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Solution

The correct option is C 1 : 3 : 5
When the ball is released from the top of tower then ratio of distance covered by the ball in first, second and third second
$h_{I} : h_{I I} : h_{I I I} = 1 : 3 : 5 : [b e c a u s e h_{n} \propto (2 n - 1)]$
$∴$ Ratio of work done $m g h_{I} : m g h_{I I} : m g h_{I I I} = 1 : 3 : 5$

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A ball is released from the top of a tower. The ratio of work done by force of gravity in first, second and third second of the motion of the ball is

The correct option is C 1 : 3 : 5 When the ball is released from the top of tower then ratio of distance covered by the ball in first, second and third second hI : hII : hIII = 1 : 3 : 5 : [because hn∝(2n−1)] ∴ Ratio of work done mghI : mghII : mghIII = 1 : 3 : 5