A ball is thrown from ground level of a field with a speed of 12.0 m/s at an angle of 45∘ with the horizontal. At what distance will it hit the field again? Take g = 10.0 m/s2.
The horizontal range = u2sin2θg
= 144m2/s210.0m/s2 = 14.4m
Thus, the ball hits the field at 14.4 m from the point of projection.