Question

# A ball is thrown from the ground to clear a wall 3 m high at a distance of 6 m and falls 18 m away from the wall. Find the angle of projection of ball.

A
tan1(13)
B
tan1(23)
C
tan1(32)
D
tan1(35)

Solution

## The correct option is C $$\displaystyle \tan ^{-1}\left ( \frac{2}{3} \right )$$$$R=6+18=24m=\frac { { u }^{ 2 }sin2\theta }{ g } \Rightarrow { u }^{ 2 }=\frac { 240 }{ 2sin\theta cos\theta } =\frac { 120 }{ sin\theta cos\theta } \\ y=xtan\theta -\frac { g{ x }^{ 2 } }{ 2{ u }^{ 2 }{ cos }^{ 2 }\theta } \Rightarrow 3=6tan\theta -\frac { 360 }{ 2{ u }^{ 2 }{ cos }^{ 2 }\theta } \\ \Rightarrow 3=6tan\theta -\frac { 360 }{ 240 } tan\theta =\frac { 9 }{ 2 } tan\theta \Rightarrow tan\theta =\frac { 2 }{ 3 }$$Physics

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