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Derivation of Position-Velocity Relation by Graphical Method

A ball is thr...

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A ball is thrown from the top of a tower in vertically upward direction. Velocity at a point h meter below the point of projection is twice of the velocity at a point h meter above the point of projection. Find the maximum height reached by the ball above the top of tower.

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Q. A ball is thrown vertically upward from the top of a tower. Velocity at depth

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Q. A ball is thrown vertically upwards from the top of a tower. Velocity at a point

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Q. A ball is thrown from the top of a tower in vertically upward direction. The speed of ball at 10 m below the top of the tower is thrice of the speed at a point 10 m above the point of projection. The maximum height reached by the ball above the top of the tower will be

एक गेंद को एक मीनार के शिखर से ऊर्ध्वाधर ऊपर की ओर फेंका जाता है। मीनार के शिखर से 10 m नीचे गेंद की चाल प्रक्षेपण बिन्दु से 10 m ऊपर स्थित एक बिन्दु पर गेंद की चाल की तिगुनी है। मीनार के शिखर से गेंद द्वारा प्राप्त की गई अधिकतम ऊँचाई होगी

Q. From the elevated point

^{'} P^{'}

a stone is projected vertically upward. When it reaches a distance

^{'} y^{'}

below the point of projection its velocity is tripled the velocity when it was at a height

^{'} y^{'}

^{'} P^{'}

. The greatest height reached by it above

^{'} P^{'}

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Derivation of Position-Velocity Relation by Graphical Method

Standard IX Physics

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