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Question

A ball is thrown up from the top of a tower with 20 m/s velocity. It took the ball 6 sec to fall to the bottom.  How much distance did the ball cover in the last second of its motion?



A

60 cm

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B

35 cm

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C

25 cm

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D

15 cm

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Solution

The correct option is D

35 cm


Last second is the 6th second

(Displacement at t = 6) - (displacement at t = 5) should give us the answer.

=20(6)+12(10)(6)2[20(5)+12(10)52]

= 120 - 180 - [100 - 125]

= - 60 - [-25]

= - 60 + 25

= - 35m

Answer = 35m as we are asking for distance.


Physics

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