Question

# A ball is thrown upward from edge of a cliff with an initial velocity of 6 m/s . How fast is it moving 1/2 s later ?(g=10 $$m/{ s }^{ 2 }$$)

Solution

## Given,Initial velocity of ball , $$u=6m/s$$acceleration on the ball, $$a=-g=-10m/s^2$$Using $$v=u+at$$Here $$t=\dfrac 12 sec$$Final velocity, $$v=6-10\times \dfrac12= 1m/s$$Physics

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