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Question

A ball is thrown upwards with an initial velocity of 20 ms1. Find the time of flight and the maximum height reached by the body respectively. (g=10 ms2)
  1. 4 s
    20 m
  2. 5 s
    25 m
  3. 4 s
    24 m
  4. 5 s
    30 m


Solution

The correct option is A 4 s
20 m
Given:
Initial velocity, u=20 ms1
Acceleration due to gravity, g=10 ms2
Upward direction is taken as positive.

At maximum height, velocity will be zero, (v = 0) as the ball will change the direction of motion. Let the maximum height be H.
Using third equation of motion, 
v2=u2+2as
02=202+2×(10)×H
H=20 m

When the ball returns to the initial point, net displacement is zero. Let the time of flight be T. Using second equation of motion, we get:
s=ut+12at2
0=20×T+12×(10)×T2
T=0 or T=4 s
Time of flight is more than zero. So, it is 4 s.

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