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Question

A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower. It hits the ground after some time with a velocity of 80m/s. The height of the tower is : (g=10m/s2)

A
340m
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B
320m
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C
300m
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D
360m
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Solution

The correct option is D 300m
The initial velocity of the ball is =20 m/s.
The final velocity of the ball is =80 m/s.

The acceleration due to gravity is =10 m/s2.

So, the height of the tower can be obtained from the expression:
v2=u2+2gh

Substitute the values in above expression:
802=202+(2×10×h)

h=640040020 m

h=600020300 m

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