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Question

A ball is thrown vertically upward with a velocity $$\mu$$ from the top of a tower. If it strikes the ground with velocity $$3\mu$$, the time taken by the ball to reach the ground is:


A
ug
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B
2ug
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C
3ug
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D
4ug
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Solution

The correct option is D $$\dfrac{4u}{g}$$

Given,

Initial velocity, $$u=-\mu \,m{{s}^{_{-1}}}$$

Final velocity, $$v=3\mu \,m{{s}^{-1}}$$

Apply first kinematic equation of motion

  $$ v=u+at $$

 $$ 3\mu =-\mu +gt $$

 $$ t=\dfrac{4\mu }{g} $$

Hence, time required to reach ground is $$\dfrac{4\mu }{g}$$ 


Physics

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