Question

# A ball is thrown vertically upward with a velocity $$\mu$$ from the top of a tower. If it strikes the ground with velocity $$3\mu$$, the time taken by the ball to reach the ground is:

A
ug
B
2ug
C
3ug
D
4ug

Solution

## The correct option is D $$\dfrac{4u}{g}$$Given, Initial velocity, $$u=-\mu \,m{{s}^{_{-1}}}$$ Final velocity, $$v=3\mu \,m{{s}^{-1}}$$ Apply first kinematic equation of motion   $$v=u+at$$  $$3\mu =-\mu +gt$$  $$t=\dfrac{4\mu }{g}$$ Hence, time required to reach ground is $$\dfrac{4\mu }{g}$$ Physics

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