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Question

A ball is thrown vertically upwards with a speed of 19.6 m/s from the top of a tower, and it returns to the base of the tower in 6s. Find the height of the tower. [Acceleration due to gravity g=9.8 m/s2]


A

60

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B

58

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C

58.8

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D

None of these

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Solution

The correct option is C

58.8


Use the equation of motion
s=ut+12at2

Here,
Let the height of the tower be h.
initial velocity u=19.6 m/s
time taken t=6 s

s=h (The magnitude of the displacement is the height of the tower. Since it is in the direction opposite to the initial velocity, its negative value is taken).

a=g=9.8 m/s2 (It is taken as negative because the direction of acceleration due to gravity is downwards, while the initial velocity is upwards).

h=(19.6×6)9.8 × 6 × 62

=58.8 m

Thus, the height of the tower is 58.8 m.


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