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Standard XII

Physics

Pure Rolling

A ball of mas...

Question

A ball of mass $0.1$ kg strikes a wall normally with a speed of $30 m s^{- 1}$ and rebounds with a speed of $20 m s^{- 1}$ . The impulse of the force exerted by the wall on the ball is

1 N s

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5 N s

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2 N s

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3 N s

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Solution

The correct option is B $5 N s$
Impulse $=$ Change in momentum
$Δ P = P_{f} - P_{i} = m (v_{f} - v_{i}) = 0.1 (30 - (- 20)) = 0.1 \times 50 = 5 N s$

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A ball of mass 0.1 kg strikes a wall normally with a speed of 30ms−1 and rebounds with a speed of 20 ms−1. The impulse of the force exerted by the wall on the ball is

The correct option is B 5 NsImpulse = Change in momentum ΔP=Pf−Pi=m(vf−vi)=0.1(30−(−20))=0.1×50=5Ns

A ball of mass $0.1$ kg strikes a wall normally with a speed of $30 m s^{- 1}$ and rebounds with a speed of $20 m s^{- 1}$ . The impulse of the force exerted by the wall on the ball is

The correct option is B $5 N s$
Impulse $=$ Change in momentum
$Δ P = P_{f} - P_{i} = m (v_{f} - v_{i}) = 0.1 (30 - (- 20)) = 0.1 \times 50 = 5 N s$