A ball of mass $0.2 k g$ is thrown against the wall $,$ the ball strikes the wall normally with velocity of $30 m / s$ sand rebounds with velocity of $20 m / s .$ Calculate the impulse of the force exerted by the ball on the wall

2 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 10 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

20 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $- 10 N$
Given $, u = 30 m / s$ $, v = 20 m / s$
$m = 0.2 k g$
impulse $-$ change in momentum of the body $,$
$= m v - m u = m (v - u)$
$= 0.2 (- 20 - 30) = - 10 N$
Hence,
option $(B)$ is correct answer.

Suggest Corrections

Similar questions

A ball of mass 0.1 kg is thrown against a wall... It strikes the wall normally with a velocity of 30 m/s and rebounds with a velocity of 20 m/s. Calculate the change in momentum of the ball...

Q. A ball of mass

0.1

kg strikes a wall normally with a speed of

30 m s^{- 1}

and rebounds with a speed of

20 m s^{- 1}

. The impulse of the force exerted by the wall on the ball is

Q. A cricket ball of mass 0.5 kg strikes a bat normally with a velocity of

30 m s^{- 1}

and rebounds with a velocity of

20 m s^{- 1}

in the opposite direction. The impulse of the force exerted by the ball on the bat is

Q. A cricket ball of mass 500 gm strikes a bat normally with a velocity 30 m/s and rebounds with a velocity 20 m/s in the opposite direction. The impulse of the force exerted by the ball on the bat is:

Q. A ball of mass 0.4 kg hits a brick wall. The ball strikes when it is moving horizontally to the left at

30 m s^{- 1}

and rebounds horizontal at 20

m s^{- 1}

. Find the impulse of the force exerted on the ball by the wall.

A ball of mass 0.2kg is thrown against the wall, the ball strikes the wall normally with velocity of 30m/s sand rebounds with velocity of 20m/s. Calculate the impulse of the force exerted by the ball on the wall

The correct option is B −10NGiven ,u=30m/s ,v=20m/s m=0.2kgimpulse − change in momentum of the body,=mv−mu=m(v−u)=0.2(−20−30)=−10NHence,option (B) is correct answer.

A ball of mass $0.2 k g$ is thrown against the wall $,$ the ball strikes the wall normally with velocity of $30 m / s$ sand rebounds with velocity of $20 m / s .$ Calculate the impulse of the force exerted by the ball on the wall

The correct option is B $- 10 N$
Given $, u = 30 m / s$ $, v = 20 m / s$
$m = 0.2 k g$
impulse $-$ change in momentum of the body $,$
$= m v - m u = m (v - u)$
$= 0.2 (- 20 - 30) = - 10 N$
Hence,
option $(B)$ is correct answer.