Question

# A ball of mass $$0.5\ kg$$ is attached to the end of a string having length $$0.5\ m.$$ The ball is rotated on a horizontal circular path about vertical axis. The maximum tension that the string can bear is $$324\ N.$$ The maximum possible value of angular velocity of ball (in $$rad/s$$) is:

A
9
B
18
C
27
D
36

Solution

## The correct option is D $$36$$We have,$$Tsin \theta = mr \omega ^{2}$$But,$$sin\theta = \dfrac{r}{L}$$$$\therefore T=mL\omega ^{2}$$$$\therefore 324= 0.5 \times 0.5 \times \omega^{2}$$$$\therefore \omega = 36\ rad/s$$Physics

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