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Question

A ball of mass $$0.5\ kg$$ is attached to the end of a string having length $$0.5\ m.$$ The ball is rotated on a horizontal circular path about vertical axis. The maximum tension that the string can bear is $$324\ N.$$ The maximum possible value of angular velocity of ball (in $$rad/s$$) is:

28714.PNG


A
9
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B
18
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C
27
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D
36
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Solution

The correct option is D $$36$$
We have,
$$Tsin \theta = mr \omega ^{2}$$
But,
$$sin\theta = \dfrac{r}{L}$$
$$\therefore T=mL\omega ^{2}$$
$$\therefore 324= 0.5 \times 0.5 \times \omega^{2}$$
$$ \therefore \omega = 36\ rad/s$$

113051_28714_ans_ba224a9cf8954f3baaacb594b0e39352.png

Physics

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