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Question

A ball of mass 0.5kg moving with speed of 2.0m/s strikes a rigid wall in a direction perpendicular to the wall and is reflected back after a perfectly elastic collision. If the ball has remained in contact with the wall for 0.5s, calculate the average force exerted on the ball by the wall.

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Solution

After reflecting back the change in momentum is nothing but 2×initial momentum =2×0.5Kg×2m/s=2Kgm/s

Average force exerted is change in momentum Δt
Given that Δt=0.5s
so by putting above value we get Force=4N

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