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Byju's Answer

Standard VIII

Physics

Conversion of P.E to K.E

A ball of mas...

Question

A ball of mass $1 k g$ moving with a velocity of $10 m / s$ at time $t = 1 s$ . At time $t = 2 s$ , it is moving with velocity of $20 m / s$ . Net force that acted on the body in this duration of time is

$100 N$

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$10 N$

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$20 N$

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$110 N$

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Solution

The correct option is B
$10 N$

Given mass $m$ = $1 k g$

Intial velocity $v_{1}$ = $10 m / s$

Final velocity $v_{2}$ = $20 m / s$

Time duration = $t_{2} - t_{1}$ = 1 s

We know that, acceleration = Rate of change of velocity

Hence, net force = mass $\times$ acceleration = $\frac{m v_{2} - m v_{1}}{t_{2} - t_{1}}$

= $\frac{20 - 10}{1}$

= $10 N$

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A ball of mass 1 kg moving with a velocity of 10 m/s at time t=1 s. At time t=2 s, it is moving with velocity of 20 m/s. Net force that acted on the body in this duration of time is

The correct option is B 10 N Given mass m = 1 kg Intial velocity v1 = 10 m/s Final velocity v2 = 20 m/s Time duration = t2−t1 = 1 s We know that, acceleration = Rate of change of velocity Hence, net force = mass × acceleration = mv2−mv1t2−t1 = 20−101 = 10 N

A ball of mass $1 k g$ moving with a velocity of $10 m / s$ at time $t = 1 s$ . At time $t = 2 s$ , it is moving with velocity of $20 m / s$ . Net force that acted on the body in this duration of time is