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Question

A ball of mass 1 kg strikes a heavy platform, elastically, moving upwards with a velocity of 5 m/s. The speed of the ball just before the collision is 10 m/s downwards. Then the impulse imparted by the platform on the ball is (in N-s


Solution

Given velocity of platform is u=5m/s and initial velocity of ball is v1=10 m/s,(Considering  velocity of platform as positive)
let v2 be final velocity of the ball after collision,
As platform is heavy w.r.t the ball, velocity of platform doesnot change.
As, collision is elastic e=1=v2uuv1
v2=2uv1
v2=2×5+10=20 m/s
Now Impulse on the ball is
J=pfpi=1×20(1×10)=30 N-s

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