A ball of mass 100 g moving with a speed of 4 m/sec strikes a horizontal surface at an angle of $30^{o}$ from the surface. The ball is reflected back with same speed and same angle of reflection find
(a) The impulse imparted to the ball
(b) change in magnitude of momentum of the ball.

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Solution

Initial normal velocity of ball toward horizontal surface, $u = 4 sin 30^{o} = 2 m s^{- 1}$

Final normal velocity of ball toward horizontal surface, $v = - 4 sin 30^{o} = - 2 m s^{- 1}$

Impulse imparted to ball, $I = F . Δ t = m Δ V = m (v - u) = 0.1 [2 - (- 2)] = 0.4 k g m s^{- 1}$

Change in momentum, $P = m Δ V = 0.4 k g m s^{- 1}$

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