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Question

A ball of mass 20 g is initially moving with a velocity of 100 ms. On applying a constant force on the ball for 0.5s, it acquires a velocity of 150 ms. Calculate the following:
(i) Initial momentum of the ball
(ii) Final momentum of the ball
(iii) Rate of change of momentum
(iv) Acceleration of the ball
(v) Magnitude of the force applied


Solution

Given, m = 20 g = 0.02 kg

Initial velocity, u = 100 ms

Time interval, t = 0.5 s

Final velocity, v = 150 ms

(i) Initial momentum of the ball = mass × initial velocity

P1 ​= mu = 0.02 kg × 100 ms = 2 kg ms1

(ii) Final momentum of the ball  = mass × final velocity

P2​ = mv = 0.02 kg × 150 ms = 3 kg ms1​​

(iii) Rate of change of momentum = 320.5 = 2.0 kg ms2​​​ = 2.0 N

(iv) Acceleration, a = 100 ms2​​​  

(v)  Force, F = mass × acceleration = 0.02 × 100 = 2.0 N

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