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Question

A ball of mass m falls vertically to the ground from a height h1 and rebound to a height h2. The change in momentum of the ball on striking ground is :

A
mg(h1h2)
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B
m(2gh2+2gh1)
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C
m2g(h1+h2)
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D
m2g(h1+h2)
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Solution

The correct option is B m(2gh2+2gh1)
Velocity just before striking the ground will be velocity gained after falling a height h1 so Vi=2gh1
Velocity just after rebounding will be the velocity needed to gain a height h2 so Vf=2gh2
so change in momentum will be ΔP=mΔV=m(VfVi)=m(2gh2+2gh1)

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