CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Relative Position

A ball of mas...

Question

A ball of mass moving with speed perfectly inelastically with another ball of measure at rest . The magnitude of impulse imparted first ball is

Open in App

Solution

The collision is perfectly inelastic Both of'em will stick together!

Then,

V = velocity of the combined mass.

Therefore,

mv = (M + m)V

V = (m/M+m)v

Impulse imparted to the 1st ball will be

MV = MmV / m+M

Suggest Corrections

thumbs-up

1

Similar questions

Q. Two identical balls each of mass 4 kg are moving towards each other with speeds 2 m/s and 3 m/s respectively, they undergo head on perfectly elastic collision. the impulse imparted by one ball on other is:

Q. A steel ball of radius

2 c m

is at rest on a frictionless surface. Another ball of radius

4 c m

moving at a velocity of

81 c m / s e c

collides elastically with first ball. After collision the smaller ball moves with speed of

Q. A ball of mass

m

moving with speed

u

collides with a smooth horizontal surface at angle

θ

with it as shown in figure. The magnitude of impulse imparted to surface by ball is [Coefficient of restitution of collision is e]

Q. A particle of mass

m

strikes a wall elastically with speed

v

30^{o}

with the wall as shown in the figure. The magnitude of impulse imparted to the ball by the wall is:

Q. A particle of mass m strikes a wall with speed v at an angle

30^{0}

with the wall elastically as shown in the figure. The magnitude of impulse imparted to the ball by the wall is :

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Relative Motion

PHYSICS

Watch in App

explore_more_icon

Explore more

Relative Position

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon