Question

A balloon blown up has a volume of $300mL$ at ${27}^{o}C$. The balloon is distended to $5/6$ of its maximum stretching capacity. The maximum temperature above which it will burst is :

• A. ${77}^{o}C$
• B. ${67}^{o}C$
• C. ${57}^{o}C$
• D. ${87}^{o}C$

Answer 1

The correct option is D ${87}^{o}C$

Maximum capacity $=300\times \frac{6}{5}=360mL$

If the volume is more than $360$, it will burst.

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\frac{300}{300}=\frac{360}{T_2}$

$T_2=360K=360-273={87}^{o}C$

Hence, the correct option is $\text{D}$