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Question

A bar is subjected to equal and opposite forces as shown in the figure. PQ is a plane making an angle θ with the cross-section of the bar. If the area of cross-section be 'a', then what is tensile stress on PQ?

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A
Fa
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B
Fcosθa
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C
Fcos2θa
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D
aFcosθ
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Solution

The correct option is D Fcos2θa
The force acting on the given plane will be Fcosθ
Also, the effective area along which the force acts is given by acosθ
Thus tensile strength on plane PQ will be:
NormalForceArea=Fcosθa/cosθ=Fcos2θa

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