A bar magnet has a magnetic moment of $0.4 A . m^{2}$ . On cutting it into two equal halves along equatorial line, each half will have a magnetic moment of :

0.4 A . m^{2}

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0.8 A . m^{2}

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0.2 A . m^{2}

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Solution

The correct option is C $0.2 A . m^{2}$
$M = 0 \cdot 4 A m^{2}$
$L_{1} = L$
$L_{2} = \frac{L}{2}$
$\frac{μ_{1}}{L_{1}} = \frac{μ_{2}}{L_{2}}$
$\frac{M}{L} = \frac{μ_{2}}{\frac{L}{2}}$

$M_{2} = \frac{M}{2}$
$= \frac{0 \cdot 4}{2}$
$= 0 \cdot 2 A m^{2}$

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A bar magnet has a magnetic moment of 0.4 A.m2. On cutting it into two equal halves along equatorial line, each half will have a magnetic moment of :

The correct option is C 0.2 A.m2M=0⋅4 Am2L1=LL2=L2μ1L1=μ2L2ML=μ2L2 M2=M2 =0⋅42 =0⋅2 Am2

A bar magnet has a magnetic moment of $0.4 A . m^{2}$ . On cutting it into two equal halves along equatorial line, each half will have a magnetic moment of :

The correct option is C $0.2 A . m^{2}$
$M = 0 \cdot 4 A m^{2}$
$L_{1} = L$
$L_{2} = \frac{L}{2}$
$\frac{μ_{1}}{L_{1}} = \frac{μ_{2}}{L_{2}}$
$\frac{M}{L} = \frac{μ_{2}}{\frac{L}{2}}$

$M_{2} = \frac{M}{2}$
$= \frac{0 \cdot 4}{2}$
$= 0 \cdot 2 A m^{2}$