A bar magnet of moment of inertia 4-9-10-2 kgm 2 vibrates in a magnetic field of induction 0-5- 10-4T- The time period of vibration is 8-8 sec- The magnetic moment of the bar magnet is -

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Byju's Answer

Standard XII

Physics

Magnetic Flux

A bar magnet ...

Question

A bar magnet of moment of inertia $4.9 \times 10^{- 2}$ kgm $^{2}$ vibrates in a magnetic field of induction $0.5 \times 10^{- 4} T$ . The time period of vibration is 8.8 sec. The magnetic moment of the bar magnet is :

350 Am

^{2}

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490 Am

^{2}

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3300 Am

^{2}

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500 Am

^{2}

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Solution

The correct option is D 500 Am $^{2}$
The time period of oscillation is given by
$T = 2 π \sqrt{\frac{I}{M B}}$
$M = \frac{4 π^{2} I}{B T^{2}}$

$M = 500 A m^{2}$

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A bar magnet of moment of inertia 4.9×10−2 kgm2 vibrates in a magnetic field of induction 0.5×10−4T. The time period of vibration is 8.8 sec. The magnetic moment of the bar magnet is :

The correct option is D 500 Am2The time period of oscillation is given byT=2π√IMBM=4π2IBT2M=500Am2

A bar magnet of moment of inertia $4.9 \times 10^{- 2}$ kgm $^{2}$ vibrates in a magnetic field of induction $0.5 \times 10^{- 4} T$ . The time period of vibration is 8.8 sec. The magnetic moment of the bar magnet is :

The correct option is D 500 Am $^{2}$
The time period of oscillation is given by
$T = 2 π \sqrt{\frac{I}{M B}}$
$M = \frac{4 π^{2} I}{B T^{2}}$

$M = 500 A m^{2}$