1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A bar Magnet of pole strength 2Am is kept in a magnetic field of induction 4×10−5Wb/m2 such that the axis of magnet makes an angle 30o with the direction of the field. The couple acting on the magnet is found to be 80×10−7Nm . Then the distance between the two poles of the magnet is :

A
20m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is C 20cmAs shown in the figure, A bar Magnet kept in a magnetic field of induction such that the axis of magnet makes an angle 30030o with the direction of the field.The couple acting on the magnet =→M×→B=mlBsinθ=80×10−7⇒2×l×4×10−5×sin300=80×10−7⇒4×10−5×l=80×10−7⇒l=20×10−2m=20cmTherefore, D is the correct option

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Electric Flux
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program