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Question

A bar of iron is 10 cm at 20o C. At 19o C it will be (a of iron = 11 X 106/o C)
 



Your Answer
A

11 ´ 10-6 cm longer

Your Answer
B

11 ´ 10-6 cm shorter

Correct Answer
C

11 ´ 10-5 cm shorter 

Your Answer
D

11 ´ 10-5 cm longer


Solution

The correct option is C

11 ´ 10-5 cm shorter 


L=L0(1+αθ)L1L2=1+α(θ)11+α(θ)2
10L2=1+11×106×201+11×106×19L2=9.99989
Length is shorten by
109.99989=0.00011=11×105 cm

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