A bar of iron is 10 cm at 20-C- At 19-C it will be -a of iron - 11 x-10-6-C- -11 - 10-5 cm longer-11 - 10-6 cm longer-11 - 10-6 cm shorter-11 - 10-5 cm shorter-

The correct option is D 11 ´ 10 5 cm shorter ...

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A bar of iron...

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A bar of iron is 10 cm at 20°C. At 19°C it will be (a of iron = 11 x 10^-6/°C)

11 ´ 10^-6 cm longer

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11 ´ 10^-6 cm shorter

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11 ´ 10^-5 cm shorter

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11 ´ 10^-5 cm longer

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