A barometer tube of radius 1 mm contains mercury surface tension 0-45 N - m and contact angle 143- - If atmospheric pressure is 75 cm of mercury column- what is height of mercury in the tube PHg -13-5 gm - cc-B- 75-4 cmC- 75 cmD- 73-2 cm

The correct option is A 74.6 cm P_0=hρ g+2T cos 53^∘r nbsp; h_0=h+2T cos 53^∘r ρ g Given h_0=75 cm h=0.75 2T cos 53^∘r ρ g =0.75 2 × 0.45 ×3510^ 3× 13.5 × 1 ...

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Standard XII

Chemistry

Real Gases

A barometer t...

Question

A barometer tube of radius $1 mm$ contains mercury (surface tension $0.45 N/m$ and contact angle $143^{\circ}$ ). If atmospheric pressure is $75 cm$ of mercury column, what is height of mercury in the tube $ρ_{H g} = 13.5 gm/cc$ .

75 cm

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74.6 cm

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75.4 cm

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73.2 cm

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Solution

The correct option is B $74.6 cm$

$P_{0} = h ρ g + \frac{2 T cos 53^{\circ}}{r}$
$h_{0} = h + \frac{2 T cos 53^{\circ}}{r ρ g}$
Given $h_{0} = 75 c m$
$h = 0.75 - \frac{2 T cos 53^{\circ}}{r ρ g}$
$= 0.75 - \frac{2 \times 0.45 \times \frac{3}{5}}{10^{- 3} \times 13.5 \times 10^{3} \times 10}$
$= 0.75 - 0.004$
$= 0.746 m$
$= 74.6 cm$

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A barometer tube of radius 1 mm contains mercury (surface tension 0.45 N/m and contact angle 143∘). If atmospheric pressure is 75 cm of mercury column, what is height of mercury in the tube ρHg=13.5 gm/cc.

The correct option is B 74.6 cm P0=hρg+2Tcos53∘r h0=h+2Tcos53∘rρg Given h0=75 cm h=0.75−2Tcos53∘rρg =0.75−2×0.45×3510−3×13.5×103×10 =0.75−0.004 =0.746 m =74.6 cm

A barometer tube of radius $1 mm$ contains mercury (surface tension $0.45 N/m$ and contact angle $143^{\circ}$ ). If atmospheric pressure is $75 cm$ of mercury column, what is height of mercury in the tube $ρ_{H g} = 13.5 gm/cc$ .