A bartender stole champagne from a bottle that comtained 50% of spirit and he replaced what he had stolen with champagne having 20% spirit. The bottle then contained only 25% spirit. How much of the bottle did he steal?

80%

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83.33%

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85.71%

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88.88%

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Solution

The correct option is B 83.33%
20% spirit is mixed with 50% spirit to get 25% spirit. The ratio of mixing would be 5 : 1 This means he stole ${\frac{5}{6}}^{t h}$ of the bottle or 83.33% of the bottle.

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A bartender stole champagne from a bottle that comtained 50% of spirit and he replaced what he had stolen with champagne having 20% spirit. The bottle then contained only 25% spirit. How much of the bottle did he steal?

The correct option is B 83.33%20% spirit is mixed with 50% spirit to get 25% spirit. The ratio of mixing would be 5 : 1 This means he stole 56th of the bottle or 83.33% of the bottle.

The correct option is B 83.33%
20% spirit is mixed with 50% spirit to get 25% spirit. The ratio of mixing would be 5 : 1 This means he stole ${\frac{5}{6}}^{t h}$ of the bottle or 83.33% of the bottle.