CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A base of a triangle QR touches a circle at S. The other two sides PQ and QR of PQR is extended such a way that they touch the circle at T and U respectively .If the perimeter of PQR is 10 cm, then length of PT is


A

10 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

9 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

5 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

8 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

5 cm



We have PT = PU (tangents from a common external points are equal )

QS = QT (tangents from a common external point are equal)

RS = RU (tangents from a common external point are equal)

PQ + QR + PR = 10 cm

2PT = PT + PU = PT + PR +SR

2 PT = PQ + QS + SR + PR

2 PT = PQ + QR + PR

PT = 10/2 = 5 cm


flag
Suggest Corrections
thumbs-up
1
BNAT
mid-banner-image