A beam has the same section throughout its length with I - 1- 108mm4- It is subjected to a uniform BM - 40kN-m- E - 2- 105N-mm2- What is the radius of curvature of the circle into which the beam will bend in the form of an arc of a circle -

ER = MI ∴ R = EIM=2× 10^5× 1× 10^840× 10^6 = 500,000 mm = 500 m ...

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Strength of Materials

Bending Stress in Sections -I

A beam has th...

Question

A beam has the same section throughout its length with $I = 1 \times 10^{8} m m^{4} .$ It is subjected to a uniform $B M = 40 k N - m, E = 2 \times 10^{5} N / m m^{2}$ . What is the radius of curvature of the circle into which the beam will bend in the form of an arc of a circle ?

1000 m

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500 m

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400 m

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350 m

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Solution

The correct option is B 500 m
$\frac{E}{R} = \frac{M}{I}$

$∴ R = \frac{E I}{M} = \frac{2 \times 10^{5} \times 1 \times 10^{8}}{40 \times 10^{6}}$

= 500,000 mm = 500 m

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A beam has the same section throughout its length with I=1×108mm4. It is subjected to a uniform BM=40kN−m,E=2×105N/mm2. What is the radius of curvature of the circle into which the beam will bend in the form of an arc of a circle ?

The correct option is B 500 mER=MI ∴R=EIM=2×105×1×10840×106 = 500,000 mm = 500 m

A beam has the same section throughout its length with $I = 1 \times 10^{8} m m^{4} .$ It is subjected to a uniform $B M = 40 k N - m, E = 2 \times 10^{5} N / m m^{2}$ . What is the radius of curvature of the circle into which the beam will bend in the form of an arc of a circle ?

The correct option is B 500 m
$\frac{E}{R} = \frac{M}{I}$

$∴ R = \frac{E I}{M} = \frac{2 \times 10^{5} \times 1 \times 10^{8}}{40 \times 10^{6}}$

= 500,000 mm = 500 m