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Question

A beam of light constituting of two wavelengths 6000A and 5200A is used to obtain interference fringes in a Young's double slit experiment. The distance between the slits is 2 mm and the distance between the plane of the slits and the screen is 120 cm. The least distance from the central maximum where the bright fringes due to both the wavelengths coincide is


Your Answer
A
3.056 cm
Your Answer
B
2.156 cm
Correct Answer
C
0.156 cm
Your Answer
D
3.156 cm

Solution

The correct option is B 0.156 cm
β1=λ1Dd;β2=λ2Dd
β1β2=λ1λ2=65005200=54
or, 4β1=5β2
Distance of 4th bright fringe due to λ1
= Distance of 5th bright fringe due to λ2
or, x=4β1=5β2
or, x=4λ1Dd=0.156 cm.

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