A beam of parallel rays is incident on a concave mirror such that they make a very small angle θ with the principle axis of the concave mirror. The distance from the focus on the focal plane where rays converge after reflection is
A
2fθ
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B
3fθ
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C
4fθ
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D
fθ
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Solution
The correct option is Dfθ
Here, focal length, PF=f Parallel rays will intersect at point F′ at a distance h below focus in the focal plane after reflection. In △FPF′, ∠FPF′=θ[∠i=∠r] and tanθ=FF′FP ⇒tanθ=hf ⇒h=ftanθ Angle θ is very small. tanθ≈θ ⇒h=fθ