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Question

A bee is making a sound by vibrating its wings 500 times per second. What is the time period of the sound?​

A
0.002 s​
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B
0.2 s​
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C
500 s​
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D
0.02 s
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Solution

The correct option is A 0.002 s​
It is given that the sound from a mosquito is produced when it vibrates its wings at an average rate of 500 vibrations per second.
It means the frequency of sound is 500 Hz.
We know that the relation between the time period and the frequency is: f=1/T or T=1/f
Substitute f=500
Therefore, T=1/500
T=0.002 s
So, the time period is 0.002 s.
Hence, the correct option is A.

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