A bike decreases its speed from $60 k m h^{- 1} t o 40 k m h^{- 1}$ in 5 s. Find the acceleration of the bike.

$2.26 m / s^{2}$

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$1.11 m / s^{2}$

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$- 1.11 m / s^{2}$

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$- 2.26 m / s^{2}$

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Solution

The correct option is C
$- 1.11 m / s^{2}$

Initial speed of the bike, $u = 60 k m h^{- 1} = 60 \times \frac{5}{18} m / s = 16.67 m s^{- 1}$
Final speed of the bike, $v = k m h^{- 1} = 40 \times \frac{5}{18} m / s = 11.11 m s^{- 1}$
Time taken to decrease the speed, t = 5 s
Acceleration, $a = \frac{v - u}{t} = \frac{11.11 - 16.67}{5} = - 1.11 m s^{- 2}$

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