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Question

A block A of mass 45 kg is placed on another block B of mass 123 kg. Now block B is displaced by external agent by 50 cm horizontally towards right. During the same time block A just reaches to the left end of block B. Initial and final positions are shown in figures. The work done on block A in ground frame is
117431.png


A
-18 J
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B
18 J
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C
36 J
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D
-36 J
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Solution

The correct option is C 18 J
As there is relative motion so kinetic friction will act on A in the direction of motion of B (or towards right).

$$f=\mu mg=0.2\times 45\times 10=90 N$$

$$S=50-30=20 cm=0.2 m$$

$$\therefore W=fS=18 \ J$$

133654_117431_ans_a020ccc9a66047fd82e168b3fb73c4fa.png

Physics

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