Question

A block having mass m collides with an another stationary block having mass $2$ m. The lighter block comes to rest after collision. If the initial velocity of first block is v, then the value of coefficient of restitution will must be?

• A. $0.5$
• B. $0.4$
• C. $0.6$
• D. $0.8$

Answer 1

The correct option is A $0.5$

By conservation of linear momentum

$mv=2m{v}^{\prime }$

$v^{\prime }=\frac{v}{2}$

The value of coefficient of restitution is

$e=\frac{Velocityofseperation}{Velocityofapproch}$

$e=\frac{\frac{v}{2}-0}{v-0}$

$e=\frac{1}{2}$

$e=0.5$

So, The value of coefficient of restitution is 0.5

Hence, A is correct option