Question

# A block having mass m collides with an another stationary block having mass $$2$$ m. The lighter block comes to rest after collision. If the initial velocity of first block is v, then the value of coefficient of restitution will must be?

A
0.5
B
0.4
C
0.6
D
0.8

Solution

## The correct option is A $$0.5$$By conservation of linear momentum$$mv=2mv'$$$$v'=\dfrac{v}{2}$$The value of coefficient of restitution is $$e=\dfrac{Velocity\ of\ seperation}{Velocity\ of\ approch}$$$$e=\dfrac{\dfrac{v}{2}-0}{v-0}$$$$e=\dfrac{1}{2}$$$$e=0.5$$So, The value of coefficient of restitution is 0.5Hence, A is correct optionPhysics

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