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Question

A block  of mass 1 kg travelling in a straight line with a velocity of 10 ms1 collides with and sticks to a stationary wooden block of mass 5 kg.
Then they both move off together in the same straight line. Calculate the total momentum just before the impact, just after the impact and the velocity of the combined object.


Your Answer
A
10 kg m s120 kg m s11.67 ms1
Your Answer
B
10 kg m s110 kg m s12 ms1
Correct Answer
C
10 kg m s110 kg m s11.67 ms1
Your Answer
D
5 kg m s110 kg m s12 ms1

Solution

The correct option is C 10 kg m s110 kg m s11.67 ms1
Given,
Mass of first block, m1=1 kg
Mass of second block, m2=5 kg
Initial velocity of first block, u1=10 m/s
Initial velocity of second block, u2=0 m/s

The momentum before collision is:
pi=m1u1+m2u2
pi=1×10+5×0
pi=10 kg m/s

Let the final velocity of the blocks be v.
Final momentum will be:
pf=(m1+m2)v
pf=(1+5)v=6v

From the law of conservation of momentum, momentum before collision should be equal to momentum after the collision as no external force was acting on the bodies. So,
pf=pi
6v=10
v=1.67 m/s

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