A block of mass 1 kg travelling in a straight line with a velocity of 10 ms−1 collides with and sticks to a stationary wooden block of mass 5 kg.
Then they both move off together in the same straight line. Calculate the total momentum just before the impact, just after the impact and the velocity of the combined object.
10 kg m s−1, 20 kg m s−1, 1.67 ms−1
10 kg m s−1, 10 kg m s−1, 2 ms−1
10 kg m s−1, 10 kg m s−1, 1.67 ms−1
5 kg m s−1, 10 kg m s−1, 2 ms−1
The correct option is C 10 kg m s−1, 10 kg m s−1, 1.67 ms−1
Mass of first block, m1=1 kg
Mass of second block, m2=5 kg
Initial velocity of first block, u1=10 m/s
Initial velocity of second block, u2=0 m/s
The momentum before collision is:
pi=10 kg m/s
Let the final velocity of the blocks be v.
Final momentum will be:
From the law of conservation of momentum, momentum before collision should be equal to momentum after the collision as no external force was acting on the bodies. So,