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Question

A block of mass 10kg is moving in x-direction with a constant speed of 10m/s. It is subjected to a retarding force F=−0.1x joule / metre during its travel from x=20 meter to x=30 metre. Its final kinetic energy will be:

A
250J
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B
325J
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C
625J
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D
475J
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Solution

The correct option is D 475J
Initial velocity u=10m/s
Acceleration =F/m=0.1x/10=0.01x m/s2
Applying third equation of motion
v2u2=2as
v2100=30202(0.01x)dx
v2100=0.01(302202)
v2=95

Final KE =0.5×mv2=0.5×10×95=475J

Hence correct answer is option D

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