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Question

A block of mass 2 kg is projected upwards along a 300 inclined plane with an initial velocity of 22 m/s. The coefficient of friction between the block and the plane is 0.2. The block moves up the plane to a distance of :

A
6.8 m
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B
8.6 m
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C
36.6 m
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D
86 m
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Solution

The correct option is B 36.6 m
Stopping distance S=u22a
a=gsinθ+μgcosθ
=9.8×12+0.2×9.8×32=6.6m/s2
Now S=u22a=22×222×6.6=36.6m

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