Question

# A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is the acceleration due to gravity) will be

A
mgcosθ
B
mgsinθ
C
mg
D
mgcosθ

Solution

## The correct option is D mgcosθ Applying pseudo force on block As block does not slip, ma cosθ=mg sinθ a=g tanθ……(1) N=masinθ+mgcosθ N=mgtanθsinθ+mgcosθ N=mgcosθ

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