CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block of mass m is placed on a surface with a vertical cross section given by y=x36. If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is

A
16 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
23 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
13 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 16 m
At equilibrium for limiting value of friction, μ=tanθ

From the question,
y=x36
tanθ=dydx=x22
μ=x22


Given μ=0.5
0.5=x22
x=1

Therefore, maximum vertical height for no slipping y=x36=16m

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon