Question

# A block of mass m is placed on a surface with a vertical cross section given by y=x36. If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is16 m23 m13 m12 m

Solution

## The correct option is A 16 mAt equilibrium for limiting value of friction, μ=tanθ From the question, y=x36 ⇒tanθ=dydx=x22  ∴μ=x22  Given μ=0.5 ⇒0.5=x22 ⇒x=1 Therefore, maximum vertical height for no slipping y=x36=16m

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